Since the first object is resting on a smooth horizontal table, the only horizontal force acting on it is the tension of the string.Using Newton's second law ( ) for the first object: T=m1⋅acap T equals m sub 1 center dot a Substitute the known values:
The solution to the problem is that the tension in the string is and the mass of the second object is 1. Identify the given values Mass of the first object ( Acceleration of the system ( Acceleration due to gravity ( We need to find the tension ( ) and the mass of the second object ( 2. Analyze the forces on the first object
m2⋅g−T=m2⋅am sub 2 center dot g minus cap T equals m sub 2 center dot a 4. Solve for the mass of the second object Rearrange the equation to solve for teen streap
m2=0.610−2.0m sub 2 equals the fraction with numerator 0.6 and denominator 10 minus 2.0 end-fraction m2=0.68.0m sub 2 equals 0.6 over 8.0 end-fraction m2=0.075 kgm sub 2 equals 0.075 kg 🏁 Final Answer The tension in the string is and the mass of the second object is
The second object is hanging and moving downward with the same acceleration . The forces acting on it are: Gravitational force acting downward: Tension acting upward: Applying Newton's second law for the downward motion: Since the first object is resting on a
m2=Tg−am sub 2 equals the fraction with numerator cap T and denominator g minus a end-fraction Substitute the values into the equation:
T=0.3 kg⋅2.0 m/s2cap T equals 0.3 kg center dot 2.0 m/s squared T=0.6 Ncap T equals 0.6 N 3. Analyze the forces on the second object Solve for the mass of the second object
m2⋅g−m2⋅a=Tm sub 2 center dot g minus m sub 2 center dot a equals cap T